Question Number 227607 by MWSuSon last updated on 10/Feb/26 Answered by MWSuSon last updated on 10/Feb/26 $${i}\:{got}\:\frac{\sqrt{\mathrm{3}}{W}}{\mathrm{3}}\:{for}\:{the}\:{reaction}\:{at}\:{C}\:{and}\:\mu=\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\: \\ $$$${The}\:{pronlem}\:{is}\:\mu=\sqrt{\mathrm{3}}\:{in}\:{the}\:{textbook}.\:{What}\:{did} \\ $$$${i}\:{do}\:{wrong}? \\ $$ Answered by…
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Question Number 227168 by mr W last updated on 04/Jan/26 $${tinku}\:{tarra}\:{sir}: \\ $$$${can}\:{you}\:{please}\:{check}\:{following}\:{issue}: \\ $$$${this}\:{is}\:{a}\:{table}\:{with}\:{frame}: \\ $$$$\begin{array}{|c|c|}{\mathrm{1}}&\hline{\mathrm{10}}\\{\mathrm{2}}&\hline{\mathrm{20}}\\\hline\end{array} \\ $$$${this}\:{is}\:{a}\:{table}\:{without}\:{frame}: \\ $$$$\begin{matrix}{\mathrm{1}}&{\mathrm{10}}\\{\mathrm{2}}&{\mathrm{20}}\end{matrix} \\ $$$${but}\:{when}\:{this}\:{post}\:{is}\:{uploaded},\:{the} \\ $$$${second}\:{table}\:{and}\:{all}\:{things}\:…
Question Number 227157 by fateh last updated on 03/Jan/26 $$\mathrm{if}\:{x}=\mathrm{4}\:\mathrm{the}\:\mathrm{equation}\:“{f}\left({x}\right)={x}^{\mathrm{2}} ''\:\mathrm{what}'\mathrm{s} \\ $$$$\mathrm{the}\:\mathrm{graph}\:\mathrm{for}\:\mathrm{this}\:\mathrm{just}\:\mathrm{curious} \\ $$ Answered by fantastic2 last updated on 03/Jan/26 Answered by TonyCWX…
Question Number 226975 by AlexandreVachon last updated on 24/Dec/25 $$ \\ $$Where are the sans serif letters? Terms of Service Privacy Policy Contact: [email protected]
Question Number 226935 by Estevao last updated on 19/Dec/25 Commented by Kassista last updated on 21/Dec/25 Commented by Kassista last updated on 21/Dec/25 Answered by…
Question Number 226936 by Estevao last updated on 19/Dec/25 Answered by Ghisom_ last updated on 19/Dec/25 $$\int\mathrm{2}^{\mathrm{ln}\:{x}} {dx}=\int{x}^{\mathrm{ln}\:\mathrm{2}} {dx}=\frac{{x}^{\mathrm{1}+\mathrm{ln}\:\mathrm{2}} }{\mathrm{1}+\mathrm{ln}\:\mathrm{2}}+{C} \\ $$ Commented by Estevao…
Question Number 226914 by Estevao last updated on 18/Dec/25 Answered by breniam last updated on 19/Dec/25 $$\mathrm{We}\:\mathrm{can}\:\mathrm{concider}\:\mathrm{it}\:\mathrm{only}\:\mathrm{for}\:\mathrm{odd}\:{n},\:\mathrm{because} \\ $$$$\mathrm{real}\:\mathrm{even}\:\mathrm{root}\:\mathrm{of}\:\mathrm{negative}\:\mathrm{number}\:\mathrm{doesn}'\mathrm{t}\:\mathrm{exist}. \\ $$$$=\underset{{n}\rightarrow\infty} {\mathrm{lim}}\sqrt[{\mathrm{2}{n}−\mathrm{1}}]{\left(\mathrm{2}{n}−\mathrm{2}\right)!\left(\mathrm{2}−\mathrm{2}{n}\right)}= \\ $$$$=\underset{{n}\rightarrow\infty} {\mathrm{lim}}\sqrt[{\mathrm{2}{n}−\mathrm{1}}]{\left(\mathrm{2}{n}−\mathrm{1}\right)!}×\sqrt[{\mathrm{2}{n}−\mathrm{1}}]{\frac{\mathrm{2}−\mathrm{2}{n}}{\mathrm{2}{n}−\mathrm{1}}}…
Question Number 226861 by Estevao last updated on 17/Dec/25 Answered by Estevao last updated on 17/Dec/25 $${Go}\:{go}\:{gooooooo} \\ $$ Answered by Tawa11 last updated on…
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