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Question Number 227919 by Spillover last updated on 01/Mar/26 $$\mathrm{1}{gm}\:{of}\:{KCl}\:{was}\:{dissolved}\:{in}\:\mathrm{130}{gm} \\ $$$${of}\:{water}\:{rising}\:{its}\:{boiling}\:{point} \\ $$$${by}\:\mathrm{0}.\mathrm{1}^{\:°} {C}.{calculate}\:{the}\:{degree}\:{of}\: \\ $$$${dissociation}\:{of}\:{salt}\:{expressed}\:{as} \\ $$$${percentage}\:{Kb}=\mathrm{0}.\mathrm{52}{C}/{mole}/{kg} \\ $$ Answered by TonyCWX last…
Question Number 227418 by Spillover last updated on 24/Jan/26 Answered by Kassista last updated on 25/Jan/26 $$\left.{a}\right)\:{At}\:{constant}\:{temperature}\:{and}\:{pressure},\:{equal}\:{volumes} \\ $$$${of}\:{all}\:{gases}\:{contain}\:{the}\:{same}\:{number}\:{of}\:{molecules}. \\ $$$$\Rightarrow\:\frac{{V}}{{n}}\:=\:{constant} \\ $$$$\left.{b}\right)\:{A}\:{mole}\:{is}\:{the}\:{amount}\:{of}\:{substance}\:{that}\:{contais} \\ $$$$\mathrm{6}.\mathrm{022}\centerdot\mathrm{10}^{\mathrm{23}}…
Question Number 227419 by Spillover last updated on 24/Jan/26 Answered by Spillover last updated on 24/Jan/26 Answered by Spillover last updated on 01/Feb/26 $${A}−{carbon}\:{cathode} \\…
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Question Number 203878 by Spillover last updated on 31/Jan/24 $$\mathrm{A}\:\mathrm{compound}\:\mathrm{M}\:\mathrm{is}\:\mathrm{composed}\:\mathrm{of}\:\mathrm{52}.\mathrm{2\%}\: \\ $$$$\mathrm{carbon}\:,\mathrm{13\%}\:\mathrm{hydrogenand}\:\mathrm{the}\:\mathrm{rest}\: \\ $$$$\mathrm{is}\:\mathrm{oxygen}.\mathrm{if}\:\mathrm{the}\:\mathrm{molecuar}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{M}\:\mathrm{is}\:\mathrm{138} \\ $$$$\left(\mathrm{a}\right)\mathrm{The}\:\mathrm{empirical}\:\mathrm{formular} \\ $$$$\left(\mathrm{b}\right)\mathrm{The}\:\mathrm{molecular}\:\mathrm{formular} \\ $$$$\mathrm{31}/\mathrm{1}/\mathrm{2024} \\ $$ Answered by Calculusboy…
Question Number 203879 by Spillover last updated on 31/Jan/24 $$\mathrm{Complete}\:\mathrm{and}\:\mathrm{balance}\:\mathrm{the}\:\mathrm{following}\:\mathrm{chemical}\:\mathrm{reaction}\: \\ $$$$\mathrm{equation} \\ $$$$\left(\mathrm{a}\right)\mathrm{Ca}\:+\:\mathrm{H}_{\mathrm{2}} \mathrm{O}\:\:\rightarrow\:\: \\ $$$$\left(\mathrm{b}\right)\mathrm{BaC}{l}\:+\:\mathrm{H}_{\mathrm{2}} \mathrm{SO}_{\mathrm{4}} \:\:\rightarrow \\ $$$$\left(\mathrm{c}\right)\mathrm{CuSO}_{\mathrm{4}} .\mathrm{5H}_{\mathrm{2}} \mathrm{O}\:\:\:\overset{\mathrm{Heat}\:\mathrm{strongly}} {\rightarrow} \\…
Question Number 116238 by Ar Brandon last updated on 02/Oct/20 $$\mathrm{How}\:\mathrm{long}\:\mathrm{does}\:\mathrm{it}\:\mathrm{take}\:\mathrm{for}\:\mathrm{the}\:\mathrm{disintegration}\:\mathrm{of} \\ $$$$\frac{\mathrm{3}}{\mathrm{10}}\:\mathrm{of}\:\mathrm{an}\:\mathrm{atom}\:\mathrm{with}\:\mathrm{radioactive}\:\mathrm{constant}\:\lambda\:? \\ $$ Answered by MrGaster last updated on 22/Jan/25 $${N}\left({t}\right)={N}_{\mathrm{0}} {e}^{−\lambda{t}} \\…
Question Number 180902 by nadovic last updated on 19/Nov/22 $$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{root}\:\mathrm{mean}\:\mathrm{square}\: \\ $$$$\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{molecules}\:\mathrm{of}\:\mathrm{a}\:{Helium} \\ $$$$\mathrm{gas}\:\mathrm{kept}\:\mathrm{in}\:\mathrm{a}\:\mathrm{gas}\:\mathrm{cylinder}\:\mathrm{at}\:\mathrm{400K}. \\ $$$$\:\:\:\:\:\:\left[{Take}\:\mathrm{R}\:=\:\mathrm{8}.\mathrm{3}\:{Jmol}^{−\mathrm{1}} {K}^{−\mathrm{1}} \right] \\ $$$${The}\:{answer}\:{provided}\:{is}\:\mathrm{1}.\mathrm{58}\:{kms}^{−\mathrm{1}} \\ $$$$\mathrm{Please}\:\mathrm{I}\:\mathrm{need}\:\mathrm{help}\:\mathrm{with}\:\mathrm{the}\:\mathrm{solution} \\ $$ Answered…