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Question-228316




Question Number 228316 by fantastic2 last updated on 06/Apr/26
Commented by fantastic2 last updated on 06/Apr/26
∡COD=40^0   ∠CED=?
$$\measuredangle{COD}=\mathrm{40}^{\mathrm{0}} \\ $$$$\angle{CED}=? \\ $$
Commented by mr W last updated on 06/Apr/26
70°
$$\mathrm{70}° \\ $$
Commented by fantastic2 last updated on 06/Apr/26
yes
$${yes} \\ $$
Commented by mr W last updated on 07/Apr/26
Commented by fantastic2 last updated on 07/Apr/26
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