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Question Number 228130 by Abod last updated on 29/Mar/26
hay  ζ(s)=ζ(σit)  for get  that → ζ(s)=0  the mini segma (σ) equals 0.5 ((1/2))  the t equals(≈) 14  and i is (√(−1))  it is ≈ (√(−14))   for get ζ(s)=0  we use ζ(0.5+[−t^(1/2) ])  and the ζ(0.5 +[−t^(1/2) ]+blank nember)≇0  with that sulation . am i get 1m$
$${hay} \\ $$$$\zeta\left({s}\right)=\zeta\left(\sigma{it}\right) \\ $$$${for}\:{get}\:\:{that}\:\rightarrow\:\zeta\left({s}\right)=\mathrm{0} \\ $$$${the}\:{mini}\:{segma}\:\left(\sigma\right)\:{equals}\:\mathrm{0}.\mathrm{5}\:\left(\frac{\mathrm{1}}{\mathrm{2}}\right) \\ $$$${the}\:{t}\:{equals}\left(\approx\right)\:\mathrm{14} \\ $$$${and}\:{i}\:{is}\:\sqrt{−\mathrm{1}} \\ $$$${it}\:{is}\:\approx\:\sqrt{−\mathrm{14}} \\ $$$$\:{for}\:{get}\:\zeta\left({s}\right)=\mathrm{0} \\ $$$${we}\:{use}\:\zeta\left(\mathrm{0}.\mathrm{5}+\left[−{t}^{\frac{\mathrm{1}}{\mathrm{2}}} \right]\right) \\ $$$${and}\:{the}\:\zeta\left(\mathrm{0}.\mathrm{5}\:+\left[−{t}^{\frac{\mathrm{1}}{\mathrm{2}}} \right]+{blank}\:{nember}\right)\ncong\mathrm{0} \\ $$$${with}\:{that}\:{sulation}\:.\:{am}\:{i}\:{get}\:\mathrm{1}{m\$} \\ $$
Commented by TonyCWX last updated on 30/Mar/26
What exactly are we solving for??  Are we solving for t given ζ(σit) = 0?  Can you provide the original question?
$$\mathrm{What}\:\mathrm{exactly}\:\mathrm{are}\:\mathrm{we}\:\mathrm{solving}\:\mathrm{for}?? \\ $$$$\mathrm{Are}\:\mathrm{we}\:\mathrm{solving}\:\mathrm{for}\:{t}\:\mathrm{given}\:\zeta\left(\sigma{it}\right)\:=\:\mathrm{0}? \\ $$$$\mathrm{Can}\:\mathrm{you}\:\mathrm{provide}\:\mathrm{the}\:\mathrm{original}\:\mathrm{question}? \\ $$
Commented by Abod last updated on 30/Mar/26
first of all , i would like to apologize  for any linguistic errors or (clunky)  englich in my previous post   is not my first language . as i am  a young student from algeria   who is still mastering the language  while exploring the deep waters  of  theoreical mathematics.  My passion for the Riemann   hypothesis and the secrets of the  0.5 critical line often makes   my thoughts run faster than my  vocabulary can keep up with !  I hope you can look past the   grammer and focus on the   Super−Symmetrice  logic and the  mathematical inventious i am   proposing   Thank you for your patience and  for the insightful comments!  My proposed formula introduces  a non−traditional symmetry   between the real (σ) and imaginary  (t) parts of the critical line .The  solution uses a (super −symmetrice)  shift;  ζ(0.5+t^(−(1/2)) +\hbar.) The result  is a perfect zero where standard   numerical  approximations usually fail   .is the logic of this symmetric  shift clear ?  do you have a facebook page . a  channel . or any preferred   platform where we can stay in  touch ?  i would love to share more of  my super−symmetric   mathematical discoveries   with you in detail.
$${first}\:{of}\:{all}\:,\:{i}\:{would}\:{like}\:{to}\:{apologize} \\ $$$${for}\:{any}\:{linguistic}\:{errors}\:{or}\:\left({clunky}\right) \\ $$$${englich}\:{in}\:{my}\:{previous}\:{post}\: \\ $$$${is}\:{not}\:{my}\:{first}\:{language}\:.\:{as}\:{i}\:{am} \\ $$$${a}\:{young}\:{student}\:{from}\:{algeria}\: \\ $$$${who}\:{is}\:{still}\:{mastering}\:{the}\:{language} \\ $$$${while}\:{exploring}\:{the}\:{deep}\:{waters} \\ $$$${of}\:\:{theoreical}\:{mathematics}. \\ $$$${My}\:{passion}\:{for}\:{the}\:{Riemann}\: \\ $$$${hypothesis}\:{and}\:{the}\:{secrets}\:{of}\:{the} \\ $$$$\mathrm{0}.\mathrm{5}\:{critical}\:{line}\:{often}\:{makes}\: \\ $$$${my}\:{thoughts}\:{run}\:{faster}\:{than}\:{my} \\ $$$${vocabulary}\:{can}\:{keep}\:{up}\:{with}\:! \\ $$$${I}\:{hope}\:{you}\:{can}\:{look}\:{past}\:{the}\: \\ $$$${grammer}\:{and}\:{focus}\:{on}\:{the}\: \\ $$$${Super}−{Symmetrice}\:\:{logic}\:{and}\:{the} \\ $$$${mathematical}\:{inventious}\:{i}\:{am}\: \\ $$$${proposing}\: \\ $$$${Thank}\:{you}\:{for}\:{your}\:{patience}\:{and} \\ $$$${for}\:{the}\:{insightful}\:{comments}! \\ $$$${My}\:{proposed}\:{formula}\:{introduces} \\ $$$${a}\:{non}−{traditional}\:{symmetry}\: \\ $$$${between}\:{the}\:{real}\:\left(\sigma\right)\:{and}\:{imaginary} \\ $$$$\left({t}\right)\:{parts}\:{of}\:{the}\:{critical}\:{line}\:.{The} \\ $$$${solution}\:{uses}\:{a}\:\left({super}\:−{symmetrice}\right) \\ $$$${shift}; \\ $$$$\zeta\left(\mathrm{0}.\mathrm{5}+{t}^{−\frac{\mathrm{1}}{\mathrm{2}}} +\backslash{hbar}.\right)\:{The}\:{result} \\ $$$${is}\:{a}\:{perfect}\:{zero}\:{where}\:{standard}\: \\ $$$${numerical} \\ $$$${approximations}\:{usually}\:{fail}\: \\ $$$$.{is}\:{the}\:{logic}\:{of}\:{this}\:{symmetric} \\ $$$${shift}\:{clear}\:? \\ $$$${do}\:{you}\:{have}\:{a}\:{facebook}\:{page}\:.\:{a} \\ $$$${channel}\:.\:{or}\:{any}\:{preferred}\: \\ $$$${platform}\:{where}\:{we}\:{can}\:{stay}\:{in} \\ $$$${touch}\:? \\ $$$${i}\:{would}\:{love}\:{to}\:{share}\:{more}\:{of} \\ $$$${my}\:{super}−{symmetric}\: \\ $$$${mathematical}\:{discoveries}\: \\ $$$${with}\:{you}\:{in}\:{detail}. \\ $$
Commented by TonyCWX last updated on 31/Mar/26
I can still understand most of your sentences, so it′s not that bad.    I have just realised that you were attepting to  solve the Riemann Hypothesis.    Sadly, I′m not an expert in this branch, so I can′t give any useful suggestions.    Keep up the great work though, just share your in this forum is enough. :)
$$\mathrm{I}\:\mathrm{can}\:\mathrm{still}\:\mathrm{understand}\:\mathrm{most}\:\mathrm{of}\:\mathrm{your}\:\mathrm{sentences},\:\mathrm{so}\:\mathrm{it}'\mathrm{s}\:\mathrm{not}\:\mathrm{that}\:\mathrm{bad}. \\ $$$$ \\ $$$$\mathrm{I}\:\mathrm{have}\:\mathrm{just}\:\mathrm{realised}\:\mathrm{that}\:\mathrm{you}\:\mathrm{were}\:\mathrm{attepting}\:\mathrm{to}\:\:\mathrm{solve}\:\mathrm{the}\:\mathrm{Riemann}\:\mathrm{Hypothesis}. \\ $$$$ \\ $$$$\mathrm{Sadly},\:\mathrm{I}'\mathrm{m}\:\mathrm{not}\:\mathrm{an}\:\mathrm{expert}\:\mathrm{in}\:\mathrm{this}\:\mathrm{branch},\:\mathrm{so}\:\mathrm{I}\:\mathrm{can}'\mathrm{t}\:\mathrm{give}\:\mathrm{any}\:\mathrm{useful}\:\mathrm{suggestions}. \\ $$$$ \\ $$$$\left.\mathrm{Keep}\:\mathrm{up}\:\mathrm{the}\:\mathrm{great}\:\mathrm{work}\:\mathrm{though},\:\mathrm{just}\:\mathrm{share}\:\mathrm{your}\:\mathrm{in}\:\mathrm{this}\:\mathrm{forum}\:\mathrm{is}\:\mathrm{enough}.\::\right) \\ $$
Commented by Abod last updated on 01/Apr/26
give me your feacbook or anstagram  and whare are you from ?
$${give}\:{me}\:{your}\:{feacbook}\:{or}\:{anstagram} \\ $$$${and}\:{whare}\:{are}\:{you}\:{from}\:? \\ $$
Commented by TonyCWX last updated on 01/Apr/26
Tony Feyman  Just a random teen in Malaysia. :D
$$\mathrm{Tony}\:\mathrm{Feyman} \\ $$$$\mathrm{Just}\:\mathrm{a}\:\mathrm{random}\:\mathrm{teen}\:\mathrm{in}\:\mathrm{Malaysia}.\::\mathrm{D} \\ $$

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