Question-228037

Question Number 228037 by fantastic2 last updated on 13/Mar/26

Answered by TonyCWX last updated on 14/Mar/26

b = Base of triangle h = Height of triangle h > b bh = 12 b^2 +h^2 = 25 ⇒ { ((b = 3)),((h = 4)) :} r = ((3 + 4 − 5)/2) = 1 A_(Circle) = π

$${b}\:=\:\mathrm{Base}\:\mathrm{of}\:\mathrm{triangle} \\ $$$${h}\:=\:\mathrm{Height}\:\mathrm{of}\:\mathrm{triangle} \\ $$$${h}\:>\:{b} \\ $$$$ \\ $$$${bh}\:=\:\mathrm{12} \\ $$$${b}^{\mathrm{2}} +{h}^{\mathrm{2}} \:=\:\mathrm{25} \\ $$$$ \\ $$$$\Rightarrow\:\begin{cases}{{b}\:=\:\mathrm{3}}\\{{h}\:=\:\mathrm{4}}\end{cases} \\ $$$$ \\ $$$${r}\:=\:\frac{\mathrm{3}\:+\:\mathrm{4}\:−\:\mathrm{5}}{\mathrm{2}}\:=\:\mathrm{1} \\ $$$${A}_{\mathrm{Circle}} \:=\:\pi \\ $$

Commented by fantastic2 last updated on 14/Mar/26