Question Number 227989 by mr W last updated on 08/Mar/26
Answered by som(math1967) last updated on 09/Mar/26
Commented by som(math1967) last updated on 09/Mar/26
$$\bigtriangleup{AED}\backsim\Delta{BEC} \\ $$$$\therefore\frac{{AE}}{{BE}}=\frac{\sqrt{\mathrm{1}}}{\:\sqrt{\mathrm{4}}}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\therefore{ar}\bigtriangleup{BED}=\mathrm{1}×\mathrm{2}=\mathrm{2}{squ} \\ $$$${ar}\bigtriangleup{BCD}=\mathrm{2}+\mathrm{4}=\mathrm{6}{Squ} \\ $$$${A}_{{yellow}} +\mathrm{1}+\mathrm{3}+\mathrm{4}=\mathrm{2}×\mathrm{6} \\ $$$$\:{A}_{{yellow}} =\mathrm{12}−\mathrm{8}=\mathrm{4}{squ} \\ $$
Commented by mr W last updated on 09/Mar/26
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