Question Number 227924 by infinityaction last updated on 02/Mar/26
Answered by mr W last updated on 02/Mar/26
$${A}_{{intersection}} \geqslant\mathrm{16}×\frac{\mathrm{0}.\mathrm{5}×\mathrm{0}.\mathrm{5}\:\mathrm{tan}\:\mathrm{22}.\mathrm{5}°}{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\mathrm{2}\left(\sqrt{\mathrm{2}}−\mathrm{1}\right)>\mathrm{0}.\mathrm{8}>\frac{\mathrm{3}}{\mathrm{4}} \\ $$
Commented by infinityaction last updated on 02/Mar/26
$${can}\:{u}\:{explain}\:{littlt}\:{bit} \\ $$$$ \\ $$
Commented by mr W last updated on 03/Mar/26
Commented by mr W last updated on 03/Mar/26
$${due}\:{to}\:{symmetry}\:{the}\:{smallest} \\ $$$${intersection}\:{area}\:{is}\:\mathrm{16}\:{times}\: \\ $$$${the}\:{hatched}\:{triangle}. \\ $$