Question Number 21280 by [email protected] last updated on 18/Sep/17
$${cosec}^{\mathrm{2}} \mathrm{67}^{\mathrm{0}} −{tan}^{\mathrm{2}} \mathrm{23}^{\mathrm{0}} = \\ $$
Answered by $@ty@m last updated on 18/Sep/17
$$\mathrm{1} \\ $$
cosec-2-67-0-tan-2-23-0-